(20x^2-12x+8)/(2x+8)

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Solution for (20x^2-12x+8)/(2x+8) equation: 


D( x )

2*x+8 = 0

2*x+8 = 0

2*x+8 = 0

2*x+8 = 0 // - 8

2*x = -8 // : 2

x = -8/2

x = -4

x in (-oo:-4) U (-4:+oo)

(20*x^2-(12*x)+8)/(2*x+8) = 0

(20*x^2-12*x+8)/(2*x+8) = 0

20*x^2-12*x+8 = 0

4*(5*x^2-3*x+2) = 0

5*x^2-3*x+2 = 0

DELTA = (-3)^2-(2*4*5)

DELTA = -31

DELTA < 0

4 = 0

4/(2*x+8) = 0

x belongs to the empty set

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